On Tue, 07 Aug 2007 22:47:38 -0700, timbo wrote: > Is it possible to pass timelocal a parameter that's already the exact > scalar output of localtime's format "Mon Jan 10 04:30:30 2007"? > > I know the perlfunc documentations for timelocal indicates that > arguments are in the form of ... > > timelocal($seconds, $minutes, $hours, $day, $month, $year) > > but I have a logfile with the above time format & want to know if > there's an easier way of reading that entry & pass it to timelocal so > as to get the epoch time.
I would be lazy and do: use Date::Parse; # From CPAN # ... read logfile, get timestamp in $datetime my $epoch = str2time( $datetime ); -- Peter Scott http://www.perlmedic.com/ http://www.perldebugged.com/ -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
