Is it possible to pass timelocal a parameter that's already the exact scalar output of localtime's format "Mon Jan 10 04:30:30 2007"?
I know the perlfunc documentations for timelocal indicates that arguments are in the form of ... timelocal($seconds, $minutes, $hours, $day, $month, $year) but I have a logfile with the above time format & want to know if there's an easier way of reading that entry & pass it to timelocal so as to get the epoch time. So far I can only think of using regex as the best solution but any smarter solution will be happily appreciated. Thanks in advance. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
