Am Montag, 18. April 2005 10.53 schrieb Vladimir D Belousov: > Charles K. Clarkson wrote: > >Aaron C. de Bruyn <mailto:[EMAIL PROTECTED]> wrote: > >: In the Perl documentation (perlintro) it says that you can find out > >: the number of elements in an array using the following syntax: > >: > >: print $myvar[$#mmyvar]; > > > > No. That prints the value of the last element of @myvar. The number
^^^ > >items in the array is the scalar evaluation of @myvar. > > > >print scalar @myvar; > > I beg your pardon, but why $myvar[$#mmyvar] is the first element of array? Read the line marked with ^^^^ above again :-) perl -le ' use strict; use warnings; my @a=(1,2,3); print $a[$#a], "\n"; # here the same as $a[2]; ' # prints: 3 > > For example: > > @myvar = qw(a b c d e f g); > > and as I can understend, $#myvar is 7, but the last element has index 6. Yes, because the first array index is 0 and thus the number of elements one more than the last index. perl -le' use strict; use warnings; my @a=(); my @b=(0); my @c=(0,1); print $#a, " / ", $#b, " / ", "\n"; ' # this prints: -1 / 0 / 1 greetings joe > > >HTH, > > > >Charles K. Clarkson > > -- > Vladimir D Belousov -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
