Re: Number of Items in Array

[Vladimir D Belousov]

John Doe wrote:
Am Montag, 18. April 2005 10.53 schrieb Vladimir D Belousov:
 

Charles K. Clarkson wrote:
   

Aaron C. de Bruyn <mailto:[EMAIL PROTECTED]> wrote:
: In the Perl documentation (perlintro) it says that you can find out
: the number of elements in an array using the following syntax:
:
: print $myvar[$#mmyvar];
  No. That prints the value of the last element of @myvar. The number
     

^^^
 

items in the array is the scalar evaluation of @myvar.
print scalar @myvar;
     

I beg your pardon, but why $myvar[$#mmyvar] is the first element of array?
   

Read the line marked with ^^^^ above again :-)
perl -le '
use strict; use warnings;
my @a=(1,2,3);
print $a[$#a], "\n"; # here the same as $a[2];
'
# prints:
3
 

I see, thank you!
I mean 'but why $myvar[$#mmyvar] is the last element of array', not 
'first' in my letter.
I thought that $#array is equal scalar(@array).
Sorry :)

 

For example:
@myvar = qw(a b c d e f g);
and as I can understend, $#myvar is 7, but the last element has index 6.
   

Yes, because the first array index is 0  and thus the number of elements one 
more 
than the last index.

perl -le'
use strict; use warnings;
my @a=();
my @b=(0);
my @c=(0,1);
print $#a, " / ", $#b, " / ", "\n";
'
# this prints:
-1 /  0 / 1
greetings joe
 

HTH,
Charles K. Clarkson
     

--
Vladimir D Belousov
   

 


--
Vladimir D Belousov
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