u235sentinel wrote: > While I've already done this with a simple shell script using grep, I > was trying to figure out how I can do the same thing in perl. > > I have an access_log from my apache web server and while I can manually > enter a date for my pattern match (which works fine), I can't seem to > get it automated properly. I suspect the $date variable may be passing > `date +%d/%b` instead of 26/Dec to the pattern matching if statement. > > FYI... when I run the program I pass the name of the file I want parsed > ( example: code.pl access_log ) > > Any thoughts on my mistake? > > Thx > > --------------------- > > Script I'm using. > > #!/usr/bin/perl > > $date=`date +%d/%b`;
Since you have a question about what the $date variable contains, here would be an excellent place to: print "I see the date as $date\n"; Let us know what prints. Joseph -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
