While I've already done this with a simple shell script using grep, I was trying to figure out how I can do the same thing in perl.

I have an access_log from my apache web server and while I can manually enter a date for my pattern match (which works fine), I can't seem to get it automated properly. I suspect the $date variable may be passing `date +%d/%b` instead of 26/Dec to the pattern matching if statement.

FYI... when I run the program I pass the name of the file I want parsed ( example: code.pl access_log )

Any thoughts on my mistake?

Thx

---------------------

Script I'm using.

#!/usr/bin/perl

 $date=`date +%d/%b`;
 print "\n";
 print "Current search pattern is $date";
 print "\nStarting parse routine...\n\n";
 while (<>) {
   if (m|$date|) {
     print $_;
  } else {
 #  print "No match.\n";
  }
}



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