Andy Anderson wrote: > I would say that this is because the "operand" && is "ANDING" the numbers. > Therefore the response the the line print 1 && 1 && 0; would be a 0. Since the > line is a "mathematical string" it is performed left to right (1 && 1 = 1, 1 && > 0 = 0). > > Hope this helps. > > Have a great day; > > Andy
Hi Andy, Right answer, wrong question. The 0 result was expected. The first statement: print 1 && 1 && 0; parses as: print ((1 && 1) && 0); The result is pretty much what we would expect. The one that gets tricky in this case is: print 1 and 1 and 0; which parses as: ((( print 1) and 1) and 0); when the interpreter successfully prints '1', the first statement returns 1, so we have: (1 and 1) and 0; The boolean operation in the first and succeeds, so we have: 1 and 0; which of course evaluates to 0, which is the return value of the overall statement, but which is never used. the overall statement is a constant--"dead code" that does nothing at all Both statement evaluate false. In the second statement, the printing is done before the statement is evaluated, because the function call takes a higher precedence than and. HTH, Joseph -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
