> dear friends: Howdy > > i have a simple doubts in reguler exepration see the the > passage that follows is stored in a variable by name v. in > the fifth line see the words like this "Next 20 ^ " now i > want delete all the charecter before ^- sign in my variable v. > > shall i use find and replace to find all the pattern before ^ > and repalce it with single space charecter. please mail me > the actual code of pattern > > $v="Description: > > /flash/hp/pb/pbhp_84x28_blu_yahoo.gif"; var pb_width=84; var > pb_height=28; var pb_FitNewWinHeight = new Array; var > pb_FitNewWinWidth = new Array; pb_FitNewWinWidth[1] = 790; >
What is all of the code above? Since its using special chars that may have problems. To simply delete everything before the '^' $description =~ s/^.*\^//; That will remove everything before the last ^ you have. So if there are two carets then it will remove both. Is that what you're trying to do or maybe you could elaborate a smidge more? > Description: > > 20 of 31,900,000 | Next 20 ^ > > Title: Java .Sun.com > > Description: > > Sun's Java page, featuring developer resources, community, > documentations, support, news, and more. java .sun.com/ > search within "; > > > > Catch all the cricket action. Download Yahoo! Score tracker > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
