dear friends: i have a simple doubts in reguler exepration see the the passage that follows is stored in a variable by name v. in the fifth line see the words like this "Next 20 ^ " now i want delete all the charecter before ^- sign in my variable v.
shall i use find and replace to find all the pattern before ^ and repalce it with single space charecter. please mail me the actual code of pattern $v="Description: /flash/hp/pb/pbhp_84x28_blu_yahoo.gif"; var pb_width=84; var pb_height=28; var pb_FitNewWinHeight = new Array; var pb_FitNewWinWidth = new Array; pb_FitNewWinWidth[1] = 790; Description: 20 of 31,900,000 | Next 20 ^ Title: Java .Sun.com Description: Sun's Java page, featuring developer resources, community, documentations, support, news, and more. java .sun.com/ search within "; Catch all the cricket action. Download Yahoo! Score tracker