$iAmAVariableHearMeRoar =~ s/%//; Rob
-----Original Message----- From: McCollum, Frank [mailto:[EMAIL PROTECTED]] Subject: substitution I want to replace a '%' symbol in a given string, but this string is not $_. Maybe this is a stupid question, but how do you specify the variable that you want the substitution to go against?? i.e. s/%//; # replaces any '%' signs in $_ with nothing but, I want to replace any '%' signs in $iAmAVariableHearMeRoar with nothing -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
