On 23/09/2013 23:17, David Christensen wrote:
beginners:I'm looking for a hash function and a related function or operator such that: H(string1 . string2) = f(H(string1), H(string2)) H(string1 . string2) = H(string1) op H(string2)
Hi David My immediate thought is that the only hash function that can work like this is the identity function (or any one-one mapping) because, by extension, the hash of a string must be equal to f(the hash of each of its characters). Not that I can prove this at present, of course! Could you explain the problem you're trying to solve? Rob -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
