You can use the following to remove the space in front $Value =~ /s/^\s+//; And for the sake of interest $Value =~ s/\s+$//; will remove any trailing spaces from a string Regards Robert Graham
-----Original Message----- From: Woz [mailto:[EMAIL PROTECTED]] Sent: 25 October 2001 12:04 To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: RE: Regular expression help!! Wow, that was fast! Thanks very much, that works well. For my next question (:-)) how can I make it strip the leading space that it leaves on the resulting string. i.e. I want it to strip 'insert_job: ' from the string - note the trailing space. At the moment I have: - ($Value)=$_=~m/(\W\w\S.*)/; ($Value)=$Value=~m/(\S.*)/; but I'm sure there's a far more elegant solution that combines it all into one. Many many thanks for your help. Warren <note to self - buy O'Reillys book on regular expressions!> -----Original Message----- From: Robert Graham Sent: Thu 25/10/2001 10:27 To: Woz; [EMAIL PROTECTED] Cc: Subject: RE: Regular expression help!! Hi You can try the following: $line = "insert_job: DUKS_rtcf_daily_log_purge job_type: c"; ($rest) = $line =~ m/(\W\w.*)/; Regards Robert -----Original Message----- From: Woz [ mailto:[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> ] Sent: 25 October 2001 11:17 To: [EMAIL PROTECTED] Subject: Regular expression help!! Hi, I'm relatively new to the wonders of Perl programming and I've yet to quite get my head around regular expressions. I'm attempting to generate a search and replace expression that will turn the following string insert_job: DUKS_rtcf_daily_log_purge job_type: c into DUKS_rtcf_daily_log_purge job_type: c i.e. remove from the beginning of the line up the space following the first : All my efforts so far remove upto the second : though and leave just 'c'. Any ideas? Any help much appreciated! Thanks, Warren
-- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
