RE: Regular expression help!!

[Woz]

Wow, that was fast!
 
Thanks very much, that works well.
For my next question (:-)) how can I make it strip the leading space
that it leaves on the resulting string. i.e. I want it to strip
'insert_job: ' from the string - note the trailing space.
 
At the moment I have: -
 
  ($Value)=$_=~m/(\W\w\S.*)/; 
  ($Value)=$Value=~m/(\S.*)/;
 
but I'm sure there's a far more elegant solution that combines it all
into one.
 
Many many thanks for your help.
 
Warren
<note to self - buy O'Reillys book on regular expressions!>


        -----Original Message----- 
        From: Robert Graham 
        Sent: Thu 25/10/2001 10:27 
        To: Woz; [EMAIL PROTECTED] 
        Cc: 
        Subject: RE: Regular expression help!!
        
        

        Hi 

        You can try the following: 

        $line = "insert_job: DUKS_rtcf_daily_log_purge job_type: c"; 
        ($rest) = $line =~ m/(\W\w.*)/; 


        Regards 
        Robert 

        -----Original Message----- 
        From: Woz [mailto:[EMAIL PROTECTED]] 
        Sent: 25 October 2001 11:17 
        To: [EMAIL PROTECTED] 
        Subject: Regular expression help!! 


        Hi, 
          
        I'm relatively new to the wonders of Perl programming and I've
yet to 
        quite get my head around regular expressions. 
        I'm attempting to generate a search and replace expression that
will 
        turn the following string 
          
        insert_job: DUKS_rtcf_daily_log_purge job_type: c 
          
        into 
          
        DUKS_rtcf_daily_log_purge job_type: c 
          
        i.e. remove from the beginning of the line up the space
following the 
        first : 
        All my efforts so far remove upto the second : though and leave
just 
        'c'. 
          
        Any ideas? 
          
        Any help much appreciated! 
          
        Thanks, 
          
        Warren 
          


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