On 2011-03-16 17:13 +0100, Olof Johansson wrote: > This is your output if the number of arguments isn't what you > expected. Guessing from > > print "firstradar velx vely \n"; > > you probably want to change > > if(@ARGV != 1){ > > to > > if(@ARGV != 2){ > > as @ARGV is a list and lists in scalar context is how many elements it > contains. Makes sense?
My brain fooled me into thinking it was a == instead of !=. What you know check is if @ARGV is not 1. I don't know why you would do this. -- - Olof Johansson - www: http://www.stdlib.se/ - {mail,xmpp}: o...@ethup.se - irc: zibri on Freenode/OFTC/IRCnet/... --
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