Hi Indra,
On 2011-03-16 22:51 +0700, ind...@students.itb.ac.id wrote:
> if(@ARGV != 1){
> print "ARGV error \n";
> print "firstradar velx vely \n";
> exit(1);
> }
...
> I got this error message :
> ARGV error
> firstradar velx vely
This is your output if the number of arguments isn't what you
expected. Guessing from
print "firstradar velx vely \n";
you probably want to change
if(@ARGV != 1){
to
if(@ARGV != 2){
as @ARGV is a list and lists in scalar context is how many elements it
contains. Makes sense?
--
- Olof Johansson
- www: http://www.stdlib.se/
- {mail,xmpp}: o...@ethup.se
- irc: zibri on Freenode/OFTC/IRCnet/...
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