Pythonic wrote: > * 2. Best solution (Pythonic)* > > >>>> import itertools >>>> c = itertools.count(9) >>>> c.next() >>>> > 9 > >>>> c.next() >>>> > 10 >
+1 Pythonic: itertools is the way to go But if you really want to implement it yourself, you need to do something like this - >>> class ns: pass ... >>> def make_incr(start): ... v = ns() ... v.count = start ... def incr(): ... v.count += 1 ... return v.count ... return incr ... >>> i = make_incr(5) >>> i() 6 >>> i() 7 It's more complex than if you did it in a functional language because of limitations on lambda and accessing variables in nested scopes. -- Siddharta Govindaraj _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
