Siddharta wrote: > Pythonic wrote: > >> * 2. Best solution (Pythonic)* >> >> >> >>>>> import itertools >>>>> c = itertools.count(9) >>>>> c.next() >>>>> >>>>> >> 9 >> >> >>>>> c.next() >>>>> >>>>> >> 10 >> >> > > +1 Pythonic: itertools is the way to go > > But if you really want to implement it yourself, you need to do > something like this - > > >>> class ns: pass > ... > >>> def make_incr(start): > ... v = ns() > ... v.count = start > ... def incr(): > ... v.count += 1 > ... return v.count > ... return incr > ... > >>> i = make_incr(5) > >>> i() > 6 > >>> i() > 7 > > It's more complex than if you did it in a functional language because of > limitations on lambda and accessing variables in nested scopes. > > -- > Siddharta Govindaraj > _______________________________________________ > > ah well, could not stop my self. More OO (?) way
>>> class Incrementer(object): ... def __init__(self, n=0): self.n = n ... def __call__(self): ... self.n += 1 ... return self.n ... >>> i = Incrementer() >>> i() 1 >>> i() 2 _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
