Thanks Bill. I'll give that a go. Bash will be fine for what I need to do.
I'd have preferred to get the volume bytes directly from the storage rather
than one step removed but this should do the trick.
-Chris-
On Wed, 10 Jan 2024, 16:41 Bill Arlofski via Bacula-users, <
bacula-users@lists.sourceforge.net> wrote:
> Hello Chris,
>
> I am replying back to the list to keep thread continuity. :)
>
>
>
> On 1/10/24 08:31, Chris Wilkinson wrote:
> > Thanks Bill
> >
> > What i was trying to do was write a script to determine the disk space
> used by each pool = sum of all volumes. Looks like i
> > would have to trace out the path from pool->storage->device from the
> conf files. More complicated than i imagined.
> >
> > Perhaps a better option would be to use bconsole 'query 11' to get the
> volume sizes.
>
>
> The easiest way to do this is to echo commands to bconsole and
> grep/sed/awk what you need:
>
> It's not pretty, and you could do so much more (and easier) with Python,
> but:
> ----8<----
> #!/bin/bash
>
> # Get the pools to iterate through
> pools=$(echo -e "list pools\nquit\n" | bconsole | grep "^| \+[0-9]" | awk
> '{print $4}')
>
> # For each pool, we can just add the bytes.
> for pool in ${pools}; do
> echo -n "Pool: ${pool} - Bytes: "
> echo -e "gui on\nlist media pool=${pool}\nquit\n" | bconsole | grep "^|
> \+[0-9]" | awk '{sum+=$10} END {print sum}'
> done
> ----8<----
>
> If you have more specific needs, or would like to see more info, formatted
> better, let me know, and maybe I can do something
> better in Python. :)
>
>
> Best regards,
> Bill
>
>
> --
> Bill Arlofski
> w...@protonmail.com
>
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