| I think you can safely change the as_expr test into | | if expr a : '\(a\)' >dev/null; then | as_expr=expr | ekse | as_expr=false | fi Just being applied, you'll be able to give it a try within a minute.
- expr ... and `expr ...` return different results on QNX 4.2.... David Morgan
- Re: expr ... and `expr ...` return different results on... akim
- Re: expr ... and `expr ...` return different result... Akim Demaille
- Re: expr ... and `expr ...` return different results on... Pavel Roskin
- FYI: Reading the $? of an assignment (Was: expr ...... Akim Demaille
- Re: expr ... and `expr ...` return different results on... David Morgan
- Re: expr ... and `expr ...` return different results on... Pavel Roskin
- Re: expr ... and `expr ...` return different results on... Akim Demaille
- Re: expr ... and `expr ...` return different results on... Lars J. Aas
- Re: expr ... and `expr ...` return different results on... Paul Eggert
- Re: expr ... and `expr ...` return different results on... Pavel Roskin
- Re: expr ... and `expr ...` return different result... Akim Demaille