OK thanks
On Dec 6, 1:56 am, "Mark Murphy" <mmur...@commonsware.com> wrote:
> > I have a library that takes a File object as a parameter to one of the
> > functions.
>
> > I am getting the file like this:
>
> > this.openFileOutput("myFile", MODE_PRIVATE)
>
> > I need to load this file from the system, however, I don't know how to
> > convert FileOutputStream to File. Or is there another way of doing
> > this?
>
> Instead of openFileOutput(), use getFilesDir() to get a File pointing to
> the directory where openFileOutput() files go. Then, use normal File
> constructors to create a File object pointing to the file you want to
> create or use.
>
> --
> Mark Murphy (a Commons Guy)http://commonsware.com
> Android App Developer Books:http://commonsware.com/books.html
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