> I have a library that takes a File object as a parameter to one of the
> functions.
>
> I am getting the file like this:
>
> this.openFileOutput("myFile", MODE_PRIVATE)
>
> I need to load this file from the system, however, I don't know how to
> convert FileOutputStream to File. Or is there another way of doing
> this?
Instead of openFileOutput(), use getFilesDir() to get a File pointing to
the directory where openFileOutput() files go. Then, use normal File
constructors to create a File object pointing to the file you want to
create or use.
--
Mark Murphy (a Commons Guy)
http://commonsware.com
Android App Developer Books: http://commonsware.com/books.html
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