@saurabh,don : let us not discuss on the equation i posted...ignore the
equation... real question is how to solve simple equation with one unknown
variable
On 28 Jan 2014 21:29, "Dave" <[email protected]> wrote:

> @Saurabh: No. It represents an equation with no solutions. "(x - 7) + 7 =
> (x + 1) - 5" reduces algebraically to "0 = -4". Since there are no values
> of x for which this is a true statement, there are no solutions.
>
> Dave
>
> On Monday, January 27, 2014 5:32:19 AM UTC-6, Saurabh Singh_cse_20094016
> wrote:
>
>> ^ No its not invalid. It just represents an equation with infinitely many
>> correct solutions depending on the domain of x.
>>
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT
>> blog:geekinessthecoolway.blogspot.com
>>
>>
>> On Mon, Jan 27, 2014 at 4:21 PM, Amol Sharma <[email protected]> wrote:
>>
>>> i din't get ur question.
>>>
>>> isn't the equation "*(x - 7) + 7 = (x + 1) - 5*"  invalid ?
>>>
>>> --
>>> Thanks and Regards,
>>> Amol Sharma
>>>
>>>
>>>
>>> On Wed, Jan 15, 2014 at 3:34 AM, Arpit Sood <[email protected]> wrote:
>>>
>>>> Equivalent to solving an infix expression using stack with a pair
>>>> (first variable, second constant) as the element
>>>>
>>>>
>>>> On Sat, Jan 11, 2014 at 6:50 AM, atul anand <[email protected]>wrote:
>>>>
>>>>> Hello,
>>>>>
>>>>> How to solve an equation with one unknown variable ?
>>>>> operator allowed are : + , -
>>>>>
>>>>> for eg .  input could be :-
>>>>>             x + ( 5 + 4 ) = 6
>>>>>             (x - 7) + 7 = (x + 1) - 5
>>>>>
>>>>> If operator also allows " * " (multiply) , then what change in
>>>>> algorithm is required.
>>>>>
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