^ No its not invalid. It just represents an equation with infinitely many correct solutions depending on the domain of x.
Saurabh Singh B.Tech (Computer Science) MNNIT blog:geekinessthecoolway.blogspot.com On Mon, Jan 27, 2014 at 4:21 PM, Amol Sharma <[email protected]> wrote: > i din't get ur question. > > isn't the equation "*(x - 7) + 7 = (x + 1) - 5*" invalid ? > > -- > Thanks and Regards, > Amol Sharma > > > > On Wed, Jan 15, 2014 at 3:34 AM, Arpit Sood <[email protected]> wrote: > >> Equivalent to solving an infix expression using stack with a pair (first >> variable, second constant) as the element >> >> >> On Sat, Jan 11, 2014 at 6:50 AM, atul anand <[email protected]>wrote: >> >>> Hello, >>> >>> How to solve an equation with one unknown variable ? >>> operator allowed are : + , - >>> >>> for eg . input could be :- >>> x + ( 5 + 4 ) = 6 >>> (x - 7) + 7 = (x + 1) - 5 >>> >>> If operator also allows " * " (multiply) , then what change in algorithm >>> is required. >>> >>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To unsubscribe from this group and stop receiving emails from it, send >>> an email to [email protected]. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected]. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected].
