The problem suggests that a character can't be more than once present and thereby it can be done by just having s bitmap and if a char repeats, any longer repeating substring will have those char repeated atleast twice, hence O(n) solution.
Also, Hasaan: how is your algo O(n2) for for->while->for chain? Best Regards Ashish Goel "Think positive and find fuel in failure" +919985813081 +919966006652 On Tue, Jun 5, 2012 at 11:42 AM, Ashish Goel <[email protected]> wrote: > Hassan, can you explain your algo? > > Best Regards > Ashish Goel > "Think positive and find fuel in failure" > +919985813081 > +919966006652 > > > On Mon, Jun 4, 2012 at 11:20 AM, Hassan Monfared <[email protected]>wrote: > >> for > > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
