Can be done in O(n) time complexity using Suffix Trees.

On Sun, Jun 3, 2012 at 1:52 PM, atul anand <[email protected]> wrote:

> can be done with O(n^2) time complexity..
>
> can it be done with O(n) complexity ???
>
> On 6/3/12, utsav sharma <[email protected]> wrote:
> > given a string tell wether it is valid or not.
> > string is valid if there is no substring which have the same substring
> > following it.
> >
> > these strings are not valid:- "stringstring","geek123123rt",
> > "abcadabcad","strngstingstrngsting"
> >
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-- 
*Thanks,
Jeevitesh Shekhar Singh.*

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