i guess....complexity would be O(2^n)
no output for 5 and 9

On Thu, Jan 19, 2012 at 3:59 PM, ADITYA KUMAR <[email protected]> wrote:

> thats a brute force solution...
> can u expalin the complexity..i think its O(n^2)
> and also there exist no solution for n < 3
>
>
> On Thu, Jan 19, 2012 at 3:36 PM, bharat b <[email protected]>wrote:
>
>> @Neeraj : will u pls explain u'r logic ...
>>
>> On 1/19/12, NEERAJ KODDHAN <[email protected]> wrote:
>> > int[] a = new int[2*n];
>> > put(a, n);
>> >
>> > static void put(int[] a,int i){
>> > if(i>0){
>> >  for(int j=0;j<a.length-i-1;j++){
>> > if(a[j]==0 && a[j+i+1]==0){
>> >  a[j]=i;
>> > a[j+i+1]=i;
>> > put(a, i-1);
>> >  a[j]=0;
>> > a[j+i+1]=0;
>> > }
>> >  }
>> > }else if(i==0){
>> > for (int k : a) {
>> >  System.out.print(k +" ");
>> > }
>> > System.out.println();
>> >  }
>> > }
>> >
>> >
>> > On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek <[email protected]
>> >wrote:
>> >
>> >> Place N number from 1 to N, in 2N positions in such a way so that there
>> >> are
>> >>
>> >> Exactly ā€œnā€ number of cells between two placed locations of number ā€œnā€.
>> >> Write a program to display numbers placed in this way.
>> >>
>> >> Example:-
>> >>
>> >> (1) One of the possible placement for 7 numbers in 14 positions is :
>> >> 5 7 2 3 6 2 5 3 4 7 1 6 1 4
>> >>
>> >>
>> >>
>> >> --
>> >>
>> >> "To Iterate is Human, To Recurse is Divine"
>> >>
>> >> --
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>>
>> **Regards
>> *
>> * <[email protected]>
>>
>> Bharat B | M.Tech II  | Computer Science & Engineering | IITM
>> *
>> *
>> *Ph: +91 8056127652*
>>
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>
>
> --
> Regards
> Aditya Kumar
> B-tech IV year
> Computer Science & Engg.
> MNNIT, Allahabad.
>
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