@Neeraj : will u pls explain u'r logic ...

On 1/19/12, NEERAJ KODDHAN <[email protected]> wrote:
> int[] a = new int[2*n];
> put(a, n);
>
> static void put(int[] a,int i){
> if(i>0){
>  for(int j=0;j<a.length-i-1;j++){
> if(a[j]==0 && a[j+i+1]==0){
>  a[j]=i;
> a[j+i+1]=i;
> put(a, i-1);
>  a[j]=0;
> a[j+i+1]=0;
> }
>  }
> }else if(i==0){
> for (int k : a) {
>  System.out.print(k +" ");
> }
> System.out.println();
>  }
> }
>
>
> On Wed, Jan 18, 2012 at 10:04 PM, Coding Geek <[email protected]>wrote:
>
>> Place N number from 1 to N, in 2N positions in such a way so that there
>> are
>>
>> Exactly ā€œnā€ number of cells between two placed locations of number ā€œnā€.
>> Write a program to display numbers placed in this way.
>>
>> Example:-
>>
>> (1) One of the possible placement for 7 numbers in 14 positions is :
>> 5 7 2 3 6 2 5 3 4 7 1 6 1 4
>>
>>
>>
>> --
>>
>> "To Iterate is Human, To Recurse is Divine"
>>
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>
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*
* <[email protected]>

Bharat B | M.Tech II  | Computer Science & Engineering | IITM
*
*
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