As per implementation can be done in log(n) using a self balancing
bst.i am not sure but i think that is how c++ maps are
implemented.this wud make the overall complexity o(n*m)+o (n*logn)
though i am not sure if this is correct analysis

On 10/19/11, saurabh singh <[email protected]> wrote:
> Sorting can be easily done in o(n) as number of chars will be
> small(256) for ascii
>
> On 10/19/11, Arun Vishwanathan <[email protected]> wrote:
>> also what would be a suitable hash function for the string?
>>
>> On Tue, Oct 18, 2011 at 1:21 PM, Arun Vishwanathan
>> <[email protected]>wrote:
>>
>>> Hmm I see but if there are m max letters in each word and there are n
>>> words
>>> in the file, then each word sort is O(mlogm) and for n words so wont it
>>> be
>>> O(nmlogm)?
>>>
>>>
>>> On Tue, Oct 18, 2011 at 12:55 PM, WgpShashank
>>> <[email protected]>wrote:
>>>
>>>> Sort the all the string , Calculate hash-value , if the two has same
>>>> hash
>>>> vale they have to be anagram. put in group on the basis of anagram.
>>>> leme know if i missed anything ?
>>>>
>>>> TC O(nlogm) n =number of words m is length of max string
>>>>
>>>>
>>>> Shashank
>>>> CSE,BIT Mesra
>>>>
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>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>


-- 
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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