Hmm I see but if there are m max letters in each word and there are n words
in the file, then each word sort is O(mlogm) and for n words so wont it be
O(nmlogm)?

On Tue, Oct 18, 2011 at 12:55 PM, WgpShashank <[email protected]>wrote:

> Sort the all the string , Calculate hash-value , if the two has same hash
> vale they have to be anagram. put in group on the basis of anagram.
> leme know if i missed anything ?
>
> TC O(nlogm) n =number of words m is length of max string
>
>
> Shashank
> CSE,BIT Mesra
>
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