I cant understand the third one
On Mon, Aug 1, 2011 at 6:09 PM, Nikhil Gupta <[email protected]>wrote:
> printf scans the arguments from right to left for any arithmetic operations
> to be performed. If found, they are evaluated according to their precedence.
>
> In 1. main()
>
>> {
>>
>> int i=1;
>>
>> printf("%d\t%d\t%d\t",i,i++,i);
>>
>> }
>>
>> output: 2 1 2
>>
>> Scanned from right. i++ is encountered. It is evaluated, but keep in mind
>> that this is post increment. So this i will still be displayed without the
>> effect of the increment operator.
>>
> Other i's are incremented though.
>
>> 2.main()
>>
>> {
>>
>> int i=1;
>>
>> printf("%d\t%d\t%d\t",i,++i,i);
>>
>> }
>>
>> output: 2 2 2
>>
>> Again, the same logic applies here as well. Here we have pre-increment. So
>> this i will have the incremented value.
>>
>>
>> 3.main()
>>
>> {
>>
>> int i=1;
>>
>> printf("%d\t%d\t%d\t",i,i++,i++);
>>
>> }
>>
>> output: 3 2 1
>>
>> I'm sure you can figure this one and the next one out.
>>
>>
>> 4.main()
>>
>> {
>>
>> int i=1;
>>
>> printf("%d\t%d\t%d\t",i,++i,++i);
>>
>> }
>>
>> output: 3 3 3
>>
>>
>>
>>
>>
>>
>>
>>
>> Regards
>> by THANU
>>
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>>
>
>
>
> --
> Nikhil Gupta
> Senior Co-ordinator, Publicity
> CSI, NSIT Students' Branch
> NSIT, New Delhi, India
>
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