printf scans the arguments from right to left for any arithmetic operations
to be performed. If found, they are evaluated according to their precedence.
In 1. main()
> {
>
> int i=1;
>
> printf("%d\t%d\t%d\t",i,i++,i);
>
> }
>
> output: 2 1 2
>
> Scanned from right. i++ is encountered. It is evaluated, but keep in mind
> that this is post increment. So this i will still be displayed without the
> effect of the increment operator.
>
Other i's are incremented though.
> 2.main()
>
> {
>
> int i=1;
>
> printf("%d\t%d\t%d\t",i,++i,i);
>
> }
>
> output: 2 2 2
>
> Again, the same logic applies here as well. Here we have pre-increment. So
> this i will have the incremented value.
>
>
> 3.main()
>
> {
>
> int i=1;
>
> printf("%d\t%d\t%d\t",i,i++,i++);
>
> }
>
> output: 3 2 1
>
> I'm sure you can figure this one and the next one out.
>
>
> 4.main()
>
> {
>
> int i=1;
>
> printf("%d\t%d\t%d\t",i,++i,++i);
>
> }
>
> output: 3 3 3
>
>
>
>
>
>
>
>
> Regards
> by THANU
>
> --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to [email protected].
> To unsubscribe from this group, send email to
> [email protected].
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>
--
Nikhil Gupta
Senior Co-ordinator, Publicity
CSI, NSIT Students' Branch
NSIT, New Delhi, India
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
