just do it.....
u will know ur query result :)
main()
{
int arr[5];
printf("%d %d\n:,sizeof(arr),sizeof(&arr));
}
On Wed, Jul 27, 2011 at 10:43 PM, aditya kumar <[email protected]
> wrote:
> sizeof calculates at compile time so their is no function call . in case of
> function it gives the size of return type of that function
>
>
> On Wed, Jul 27, 2011 at 9:41 PM, Abhinav Arora
> <[email protected]>wrote:
>
>> ya Amit is right...
>> sizeof(main()) will return 4 because main will return an
>> integer.....however it will not execute main()..and sizeof(&main) will give
>> 4 too but this time it is 4 because &main is a pointer to main
>>
>> another example
>>
>>
>> #include<stdio.h>
>> #include<conio.h>
>> double foo();
>> main()
>> {
>> int a,b,c;
>> int **p;
>> printf("%d",sizeof(foo()));
>> getch();
>> }
>> double foo()
>> {
>> printf("Hi");
>> return 123.45;
>> }
>>
>>
>> Here sizeof(foo())will return 8 which is the size of double. However it
>> will not run the function foo.....and sizeof(&foo) gives 4 ...as it is a
>> pointer to function foo
>>
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--
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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