sizeof calculates at compile time so their is no function call . in case of function it gives the size of return type of that function
On Wed, Jul 27, 2011 at 9:41 PM, Abhinav Arora <[email protected]>wrote: > ya Amit is right... > sizeof(main()) will return 4 because main will return an > integer.....however it will not execute main()..and sizeof(&main) will give > 4 too but this time it is 4 because &main is a pointer to main > > another example > > > #include<stdio.h> > #include<conio.h> > double foo(); > main() > { > int a,b,c; > int **p; > printf("%d",sizeof(foo())); > getch(); > } > double foo() > { > printf("Hi"); > return 123.45; > } > > > Here sizeof(foo())will return 8 which is the size of double. However it > will not run the function foo.....and sizeof(&foo) gives 4 ...as it is a > pointer to function foo > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/IP5eG_wpP7oJ. > > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
