ok...!
#include<stdio.h>
#include<stddef.h>
struct node{
int a;
char b[5];
struct node *link;
};
main()
{
int a;
a=sizeof(struct node);
printf("%d",a);
getchar();
return 0;
}
why is its output : 16?
Sudnt it be 4(int a) +5(char b[5] string) +9(link)= 18..?
On 7/26/11, Akshata Sharma <[email protected]> wrote:
> char *s[5] is an array of 5 char pointers. A pointer is an int, of size 4
> bytes. So, 5*4 = 20 bytes
>
> On Tue, Jul 26, 2011 at 7:11 PM, Puneet Gautam
> <[email protected]>wrote:
>
>> @everyone:
>> I have this mind strangling doubt..!!!
>>
>> Why is "char *s[5]" of 20 bytes...?
>>
>> yes the output is 28...
>>
>> On 7/26/11, Don <[email protected]> wrote:
>> > A reasonable guess would be 28 bytes. But the size of a structure is
>> > implementation dependent, and therefore, some other result could be
>> > correct as well.
>> > Don
>> >
>> > On Jul 26, 7:40 am, Puneet Gautam <[email protected]> wrote:
>> >> #include<stdio.h>
>> >> #include<stddef.h>
>> >> struct node{
>> >> int a;
>> >> char *b[5];
>> >> struct node *link;
>> >> };
>> >> main()
>> >> {
>> >> int a;
>> >> a=sizeof(struct node);
>> >> printf("%d",a);
>> >> getchar();
>> >> return 0;
>> >> }
>> >>
>> >> Whats the output..?
>> >
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