@akshata: here padding wont come into picture coz int a =4byte, char
*b[5]=4*5byte, *link=4byte all are multiple of 4 . ans will be 28 byte

On Tue, Jul 26, 2011 at 6:42 PM, Akshata Sharma
<[email protected]>wrote:

> why isn't padding done here? We have seen previous posts on size of
> structures, where due to padding, the size was not just the sum of size of
> datatypes, but also padded bytes.
> like here, int (4 bytes), then why is 3 bytes not padded after this, before
> char* arr[5] (20 bytes)?
>
>
> On Tue, Jul 26, 2011 at 6:16 PM, sunny agrawal <[email protected]>wrote:
>
>> 4+20+4 = 28 bytes it should be i think
>>
>> On Tue, Jul 26, 2011 at 6:10 PM, Puneet Gautam 
>> <[email protected]>wrote:
>>
>>> #include<stdio.h>
>>> #include<stddef.h>
>>> struct node{
>>>       int a;
>>>       char *b[5];
>>>       struct node *link;
>>>       };
>>> main()
>>> {
>>>      int a;
>>>      a=sizeof(struct node);
>>>      printf("%d",a);
>>>      getchar();
>>>      return 0;
>>>      }
>>>
>>> Whats the output..?
>>>
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>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
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