@aditi: the "%2" in each of these printf statements is redundant coz
it is "1%2"...and "%" has higher precedence over left or right
shifts..thats y output of say :
#include<stdio.h>
main()
{
int i=1;
printf("\n%d%d ",i<<=2,i<<=1%2);
return 0;
}
is 8 8
1 gets left shifted twice in i<<=2, becomes 4
then i<<1%2 concludes to i<<1 as 1%2 is 1 only..
i<<1 ,makes i=8 and hence
8 8 is printed.....
On 7/25/11, Puneet Gautam <[email protected]> wrote:
> @rajeev: hey...does printf evaluate an expression right to left
> without considering any priority of operators..?
> Pls reply asap..
>
>
>
> On 7/25/11, Puneet Gautam <[email protected]> wrote:
>> @aditi: y dont u try it out urself considering the priorities of
>> different operators used here...!!
>> that would help...
>>
>> On 7/25/11, aditi garg <[email protected]> wrote:
>>> Can u plz elaborate...im not able to understand...
>>>
>>> On Mon, Jul 25, 2011 at 11:04 PM, rajeev bharshetty
>>> <[email protected]>wrote:
>>>
>>>> @sameer I think that is right
>>>>
>>>>
>>>> On Mon, Jul 25, 2011 at 11:02 PM, [email protected] <
>>>> [email protected]> wrote:
>>>>
>>>>> its because of side effect where value of i is getting changed twice
>>>>> in
>>>>> a
>>>>> single line.
>>>>> correct me if i am wrong :)
>>>>>
>>>>> *Muthuraj R.
>>>>> 4TH Year BE.**
>>>>> Information Science Dept*
>>>>> *PESIT, Bengaluru .
>>>>> *
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> On Mon, Jul 25, 2011 at 11:01 PM, geek forgeek
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> y not the output is 3 2 coz on right to left evaluation of printf i
>>>>>> shud be left shifted by 1 bit wgich shud make it 2 ??
>>>>>>
>>>>>>
>>>>>> On Mon, Jul 25, 2011 at 10:28 AM, [email protected] <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>> yeah output
>>>>>>> 0
>>>>>>> 1 1
>>>>>>> *is dis because of side effect? *
>>>>>>> * *
>>>>>>> *
>>>>>>> *
>>>>>>> *Muthuraj R.
>>>>>>> 4TH Year BE.**
>>>>>>> Information Science Dept*
>>>>>>> *PESIT, Bengaluru .
>>>>>>> *
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Mon, Jul 25, 2011 at 10:49 PM, Deoki Nandan
>>>>>>> <[email protected]>wrote:
>>>>>>>
>>>>>>>> run on gcc compiler it would be
>>>>>>>> 0
>>>>>>>> 1 1
>>>>>>>>
>>>>>>>>
>>>>>>>> On Mon, Jul 25, 2011 at 10:35 PM, geek forgeek
>>>>>>>> <[email protected]>wrote:
>>>>>>>>
>>>>>>>>> 1.
>>>>>>>>> #include<stdio.h>
>>>>>>>>> main()
>>>>>>>>> {
>>>>>>>>> int i=1;
>>>>>>>>> printf("\n%d",i^=1%2);
>>>>>>>>> printf("\n%d %d",i^=1%2,i<<=1%2);
>>>>>>>>> return 0;
>>>>>>>>> }
>>>>>>>>>
>>>>>>>>> output 3 3
>>>>>>>>> hey shudnt the output be 3 2
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> --
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>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>> --
>>>>>>>> **With Regards
>>>>>>>> Deoki Nandan Vishwakarma
>>>>>>>>
>>>>>>>> *
>>>>>>>> *
>>>>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> Regards
>>>> Rajeev N B <http://www.opensourcemania.co.cc>
>>>>
>>>>
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>>>
>>>
>>>
>>> --
>>> Aditi Garg
>>> Undergraduate Student
>>> Electronics & Communication Divison
>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>> Sector 3, Dwarka
>>> New Delhi
>>>
>>> 9718388816
>>>
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>>
>
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