Ingore the above code. It is wrong.

On Thu, Jul 21, 2011 at 2:39 PM, Pankaj <[email protected]> wrote:

> int n,temp,pow2=1;
> cin>>n;
> temp=n;
> while(temp){
>   if(temp%2==) n-=pow2;
>    pow2*=2;
>    temp=temp/2;
>   }
>
> On Thu, Jul 21, 2011 at 2:08 PM, Vivek Srivastava <
> [email protected]> wrote:
>
>> I forgot to mention that you have to program the problem in any language
>> of your choice.But C will be preferred.
>>
>>
>> On Thu, Jul 21, 2011 at 1:49 PM, karthiga m <[email protected]>wrote:
>>
>>> i got this solution ..
>>>  assuming when  n=1 .... 1st person  will be alive
>>> when n=2    1st person will be alive ,
>>> when n=3     3rd person will be alive
>>> when n=4     1st person will be alive
>>> when n=5   3rd one will be alive
>>> when n=6  5th person will be alive
>>> when n=7  7th one wil be alive
>>> when n=8   1st person will be alive
>>> ..............when n=16 1st person will be live
>>> when n=32 1st person will be alive..by this we can conclude that for
>>> n=1,2,4,8,16,32,64 the 1st person will not die...
>>> between this the odd one's will not die..
>>> the sequence will be like
>>> between n=2 and n=4 ..3rd one will not die,
>>> same as between n=4 and n=8   3rd,5th,7th one will not die...
>>> so by filling odd no's between the values for what we getting one we
>>> can find the person who will be alive.....
>>> hence for 2 POWER n  the 1st person will be alive
>>> if anything wrong in this pls correct me..!!!
>>>
>>> On 7/21/11, SAMM <[email protected]> wrote:
>>> > I think it is related to Joshepus problm... ckeck wikipedia for more
>>> > info.....
>>> >
>>> > On 7/20/11, Vivek Srivastava <[email protected]> wrote:
>>> >> If n people are standing in a circle ,they start shooting the person
>>> >> standing next to their neighbour.If they start firing in this way ,
>>> >> determine who will be alive after this sequence??
>>> >>
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>>> >
>>> >
>>> > --
>>> > Somnath Singh
>>> >
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>

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