I forgot to mention that you have to program the problem in any language of
your choice.But C will be preferred.

On Thu, Jul 21, 2011 at 1:49 PM, karthiga m <[email protected]>wrote:

> i got this solution ..
>  assuming when  n=1 .... 1st person  will be alive
> when n=2    1st person will be alive ,
> when n=3     3rd person will be alive
> when n=4     1st person will be alive
> when n=5   3rd one will be alive
> when n=6  5th person will be alive
> when n=7  7th one wil be alive
> when n=8   1st person will be alive
> ..............when n=16 1st person will be live
> when n=32 1st person will be alive..by this we can conclude that for
> n=1,2,4,8,16,32,64 the 1st person will not die...
> between this the odd one's will not die..
> the sequence will be like
> between n=2 and n=4 ..3rd one will not die,
> same as between n=4 and n=8   3rd,5th,7th one will not die...
> so by filling odd no's between the values for what we getting one we
> can find the person who will be alive.....
> hence for 2 POWER n  the 1st person will be alive
> if anything wrong in this pls correct me..!!!
>
> On 7/21/11, SAMM <[email protected]> wrote:
> > I think it is related to Joshepus problm... ckeck wikipedia for more
> > info.....
> >
> > On 7/20/11, Vivek Srivastava <[email protected]> wrote:
> >> If n people are standing in a circle ,they start shooting the person
> >> standing next to their neighbour.If they start firing in this way ,
> >> determine who will be alive after this sequence??
> >>
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