computer organization carl hamacher. computer system architecture by Morris
Mano. Computer organization and architecture by william stallings.. if u
dont have these refer wikipedia.

On Wed, Jul 13, 2011 at 10:59 PM, Piyush Kapoor <[email protected]> wrote:

> Will u guyz pls tell me frm where do u study terms like "endian" ,it is a
> pity i had to google it  :( :(
>
>
> On Wed, Jul 13, 2011 at 10:30 PM, Anika Jain <[email protected]>wrote:
>
>> ya thts ryt, for big endian it will be 64 -90 102 102
>>
>>
>> On Wed, Jul 13, 2011 at 10:22 PM, sunny agrawal 
>> <[email protected]>wrote:
>>
>>> I think it is machine dependent and current output is for a little endian
>>> machine
>>> and output should be reverse for a big endian machine
>>>
>>> On Wed, Jul 13, 2011 at 10:18 PM, Anika Jain <[email protected]>wrote:
>>>
>>>> it is not unsigned its signed but positive thts y it is 0..
>>>> the order isnt reversed.. look at the code, the code 1st prints lowest
>>>> order byte then next and then next and then highest soo output is 102 102
>>>> -90 64
>>>>
>>>>
>>>> On Wed, Jul 13, 2011 at 8:08 PM, Piyush Kapoor <[email protected]>wrote:
>>>>
>>>>> why is the order of numbers reversed?
>>>>>
>>>>>
>>>>> On Wed, Jul 13, 2011 at 8:07 PM, Anika Jain <[email protected]>wrote:
>>>>>
>>>>>> sorry its 01000000 not 11000000 coz 5.2 is a positive no. so sign bit
>>>>>> is 0
>>>>>>
>>>>>>
>>>>>> On Wed, Jul 13, 2011 at 7:58 PM, Piyush Kapoor 
>>>>>> <[email protected]>wrote:
>>>>>>
>>>>>>> Shouldn't the value of "11000000" be -64????
>>>>>>>
>>>>>>>
>>>>>>> On Wed, Jul 13, 2011 at 4:53 PM, Anika Jain 
>>>>>>> <[email protected]>wrote:
>>>>>>>
>>>>>>>> binary equivalent of 5.2 is
>>>>>>>> 101.0011001100110011001100110011(nonterminating)..
>>>>>>>>
>>>>>>>> now it is actually stored in normalised frorm in 32 bits..
>>>>>>>> like this
>>>>>>>> <--1 bit for sign---><-----8 bits for exponent-----><--------23 bits
>>>>>>>> for fraction------>
>>>>>>>> this is from higher order byte to lower order for little endian..
>>>>>>>>
>>>>>>>> if no. is positive sign bit is 0 else it is 1
>>>>>>>>
>>>>>>>> The rule says change your floating point no. in such a form that
>>>>>>>> after 1st digit that is 1 decimal point comes sooo
>>>>>>>> here it becomes like
>>>>>>>> 1.0100110011001100110011001100110011(nonterminating) * 2^2
>>>>>>>>
>>>>>>>> so i here get an exponent of 2 as 2 here.. now in exponent 8 bits
>>>>>>>> this exponent is stored as 127+exponent so here it becomes 10000001..
>>>>>>>>
>>>>>>>> now fraction here is clearly value after the decimal point i.e.
>>>>>>>> 01001100110011001100110011001100110011(non terminationg) but only 1st 
>>>>>>>> 23
>>>>>>>> bits are saved rest are left
>>>>>>>>
>>>>>>>> so finally wht we get is:
>>>>>>>>
>>>>>>>> 11000000 10100110 01100110 01100110
>>>>>>>> (64)          (-90)         (102)        (102)
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>> On Wed, Jul 13, 2011 at 2:49 PM, Piyush Kapoor <[email protected]
>>>>>>>> > wrote:
>>>>>>>>
>>>>>>>>> why do we need a NthIntWithKBits() in this topic?
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Tue, Jul 12, 2011 at 7:58 AM, oppilas . <
>>>>>>>>> [email protected]> wrote:
>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On Mon, Jul 11, 2011 at 5:54 PM, Piyush Kapoor <
>>>>>>>>>> [email protected]> wrote:
>>>>>>>>>>
>>>>>>>>>>> Can anybody give a full explanation
>>>>>>>>>>>
>>>>>>>>>>> http://ideone.com/K1QmV
>>>>>>>>>>
>>>>>>>>>>>  On Sat, Jul 9, 2011 at 10:49 PM, sunny agrawal <
>>>>>>>>>>> [email protected]> wrote:
>>>>>>>>>>>
>>>>>>>>>>>> try to find out the binary representation of float value 5.2
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On Sat, Jul 9, 2011 at 10:46 PM, Sangeeta <
>>>>>>>>>>>> [email protected]> wrote:
>>>>>>>>>>>>
>>>>>>>>>>>>> int main(){
>>>>>>>>>>>>> int i;
>>>>>>>>>>>>> float a=5.2;
>>>>>>>>>>>>> char *ptr;
>>>>>>>>>>>>> ptr=(char *)&a;
>>>>>>>>>>>>> for(i=0;i<=3;i++)
>>>>>>>>>>>>> printf("%d ",*ptr++);
>>>>>>>>>>>>> }
>>>>>>>>>>>>>
>>>>>>>>>>>>> output:
>>>>>>>>>>>>>  102 102 -90 64.explain?
>>>>>>>>>>>>>
>>>>>>>>>>>>> --
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>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> --
>>>>>>>>>>>> Sunny Aggrawal
>>>>>>>>>>>> B-Tech IV year,CSI
>>>>>>>>>>>> Indian Institute Of Technology,Roorkee
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>>  --
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>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> --
>>>>>>>>>>> *Regards,*
>>>>>>>>>>> *Piyush Kapoor,*
>>>>>>>>>>> *CSE-IT-BHU*
>>>>>>>>>>>
>>>>>>>>>>>  --
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>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> --
>>>>>>>>> *Regards,*
>>>>>>>>> *Piyush Kapoor,*
>>>>>>>>> *CSE-IT-BHU*
>>>>>>>>>
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>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> --
>>>>>>> *Regards,*
>>>>>>> *Piyush Kapoor,*
>>>>>>> *CSE-IT-BHU*
>>>>>>>
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>>>>>>
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>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> *Regards,*
>>>>> *Piyush Kapoor,*
>>>>> *CSE-IT-BHU*
>>>>>
>>>>>  --
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>>>>
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>>>
>>>
>>>
>>> --
>>> Sunny Aggrawal
>>> B-Tech IV year,CSI
>>> Indian Institute Of Technology,Roorkee
>>>
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>>
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>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
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>



-- 
Warm Regards,
Sunny T

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