sorry its 01000000 not 11000000 coz 5.2 is a positive no. so sign bit is 0

On Wed, Jul 13, 2011 at 7:58 PM, Piyush Kapoor <[email protected]> wrote:

> Shouldn't the value of "11000000" be -64????
>
>
> On Wed, Jul 13, 2011 at 4:53 PM, Anika Jain <[email protected]>wrote:
>
>> binary equivalent of 5.2 is
>> 101.0011001100110011001100110011(nonterminating)..
>>
>> now it is actually stored in normalised frorm in 32 bits..
>> like this
>> <--1 bit for sign---><-----8 bits for exponent-----><--------23 bits for
>> fraction------>
>> this is from higher order byte to lower order for little endian..
>>
>> if no. is positive sign bit is 0 else it is 1
>>
>> The rule says change your floating point no. in such a form that after 1st
>> digit that is 1 decimal point comes sooo
>> here it becomes like 1.0100110011001100110011001100110011(nonterminating)
>> * 2^2
>>
>> so i here get an exponent of 2 as 2 here.. now in exponent 8 bits this
>> exponent is stored as 127+exponent so here it becomes 10000001..
>>
>> now fraction here is clearly value after the decimal point i.e.
>> 01001100110011001100110011001100110011(non terminationg) but only 1st 23
>> bits are saved rest are left
>>
>> so finally wht we get is:
>>
>> 11000000 10100110 01100110 01100110
>> (64)          (-90)         (102)        (102)
>>
>>
>>
>> On Wed, Jul 13, 2011 at 2:49 PM, Piyush Kapoor <[email protected]>wrote:
>>
>>> why do we need a NthIntWithKBits() in this topic?
>>>
>>>
>>> On Tue, Jul 12, 2011 at 7:58 AM, oppilas . <[email protected]>wrote:
>>>
>>>>
>>>>
>>>> On Mon, Jul 11, 2011 at 5:54 PM, Piyush Kapoor <[email protected]>wrote:
>>>>
>>>>> Can anybody give a full explanation
>>>>>
>>>>> http://ideone.com/K1QmV
>>>>
>>>>>  On Sat, Jul 9, 2011 at 10:49 PM, sunny agrawal <
>>>>> [email protected]> wrote:
>>>>>
>>>>>> try to find out the binary representation of float value 5.2
>>>>>>
>>>>>>
>>>>>> On Sat, Jul 9, 2011 at 10:46 PM, Sangeeta <[email protected]>wrote:
>>>>>>
>>>>>>> int main(){
>>>>>>> int i;
>>>>>>> float a=5.2;
>>>>>>> char *ptr;
>>>>>>> ptr=(char *)&a;
>>>>>>> for(i=0;i<=3;i++)
>>>>>>> printf("%d ",*ptr++);
>>>>>>> }
>>>>>>>
>>>>>>> output:
>>>>>>>  102 102 -90 64.explain?
>>>>>>>
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>>>>>>
>>>>>>
>>>>>> --
>>>>>> Sunny Aggrawal
>>>>>> B-Tech IV year,CSI
>>>>>> Indian Institute Of Technology,Roorkee
>>>>>>
>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> *Regards,*
>>>>> *Piyush Kapoor,*
>>>>> *CSE-IT-BHU*
>>>>>
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>>>
>>>
>>>
>>> --
>>> *Regards,*
>>> *Piyush Kapoor,*
>>> *CSE-IT-BHU*
>>>
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>
>
>
> --
> *Regards,*
> *Piyush Kapoor,*
> *CSE-IT-BHU*
>
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