@ritu
how would you find a successor without extra space if you dont have a parent
pointer ?
for Instance from the right most node of left subtree to the parent of left
subtree(root) ?
@Juver++
Internal stack does count as extra space !!


On Wed, Jan 26, 2011 at 3:02 PM, ritu <[email protected]> wrote:

> No,no extra space is needed.
> Right children which are NULL pointers are replaced with pointer to
> successor.
>
> On Jan 26, 1:18 pm, nphard nphard <[email protected]> wrote:
> > If you convert the given binary tree into right threaded binary tree,
> won't
> > you be using extra space while doing so? Either the given tree should
> > already be right-threaded (or with parent pointers at each node) or
> internal
> > stack should be allowed for recursion but no extra space usage apart from
> > that.
> >
> > On Wed, Jan 26, 2011 at 3:04 AM, ritu <[email protected]> wrote:
> > > it can be done in O(n) time using right threaded binary tree.
> > > 1.Convert the tree to right threaded tree.
> > > right threaded tree means every node points to its successor in
> > > tree.if right child is not NULL,then it already contains a pointer to
> > > its successor Else it needs to filled up as following
> > >      a. For every node x,go to the last node in its left subtree and
> > > mark the right child of that node as x.
> > > It Can be done in O(n) time if tree is a balanced tree.
> >
> > > 2. Now,Traverse the tree with Inorder Traversal without using
> > > additional space(as successor of any node is available O(1) time) and
> > > keep track of 5th largest element.
> >
> > > Regards,
> > > Ritu
> >
> > > On Jan 26, 8:38 am, nphard nphard <[email protected]> wrote:
> > > > Theoretically, the internal stack used by recursive functions must be
> > > > considered for space complexity.
> >
> > > > On Mon, Jan 24, 2011 at 5:40 AM, juver++ <[email protected]>
> wrote:
> > > > > internal stack != extra space
> >
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