If you convert the given binary tree into right threaded binary tree, won't
you be using extra space while doing so? Either the given tree should
already be right-threaded (or with parent pointers at each node) or internal
stack should be allowed for recursion but no extra space usage apart from
that.

On Wed, Jan 26, 2011 at 3:04 AM, ritu <[email protected]> wrote:

> it can be done in O(n) time using right threaded binary tree.
> 1.Convert the tree to right threaded tree.
> right threaded tree means every node points to its successor in
> tree.if right child is not NULL,then it already contains a pointer to
> its successor Else it needs to filled up as following
>      a. For every node x,go to the last node in its left subtree and
> mark the right child of that node as x.
> It Can be done in O(n) time if tree is a balanced tree.
>
> 2. Now,Traverse the tree with Inorder Traversal without using
> additional space(as successor of any node is available O(1) time) and
> keep track of 5th largest element.
>
>
>
> Regards,
> Ritu
>
> On Jan 26, 8:38 am, nphard nphard <[email protected]> wrote:
> > Theoretically, the internal stack used by recursive functions must be
> > considered for space complexity.
> >
> > On Mon, Jan 24, 2011 at 5:40 AM, juver++ <[email protected]> wrote:
> > > internal stack != extra space
> >
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