> From: zfs-discuss-boun...@opensolaris.org [mailto:zfs-discuss- > boun...@opensolaris.org] On Behalf Of Edward Ned Harvey > > it depends on the total number of used blocks that must > be resilvered on the resilvering device, multiplied by the access time for > the resilvering device.
It is a safe assumption, if you've got a lot of devices in a vdev, that you've probably got a lot of data in the vdev. And therefore the resilver time for that vdev will be large. If you break your pool up into a bunch of mirrors, then the most data you'll have in any one vdev is 1-disk worth of data. If you have a vdev whose usable capacity is M times a single disk, chances are, the amount of data you have in the vdev is L times larger than the amount of data you would have had in each vdev if you were using mirrors. (I'm intentionally leaving the relationship between M and L vague, but both are assumed to be > 1 and approaching the number of devices in the vdev minus parity drives). Therefore the resilver time for that vdev will be roughly L times the resilver time of a mirror. _______________________________________________ zfs-discuss mailing list zfs-discuss@opensolaris.org http://mail.opensolaris.org/mailman/listinfo/zfs-discuss
