Ahhh! So thats how the formula works. That makes perfect sense.

Lets take my case as a scenario:

Each of my vdevs is 10 disk RaidZ2 (8 data + 2 Parity). Using 128K stripe, I'll 
have 128K/8 = 16K blocks per data drive & 16K blocks per parity drive. That 
fits both 512B & 4KB.

It works in my favour that I'll have high average file sizes (>250MB). So I'll 
see minimal effect of the "fragmentation" mentioned.
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