This is an odd question, to be certain, but I need to find out what size a 1.5 TB drive is to help me create a sparse/fake array.
Basically, if I could have someone do a dd if=<1.5 TB disk> of=<somefile> and then post the ls -l size of that file, it would greatly assist me. Here's what I'm doing: I have a 1 TB drive with my data on it (NTFS) and a second 1 TB drive that I want to move my data on to. However, I eventually want to have 6 x 1.5 TB drives for this array (with raidz2 for 6 TB of usable storage - I have a ton of additional drives with data). I can't afford the drives now, but want to get it ready for when I can, so here's my plan: 1) Create a ZFS volume with the 1 TB drive that's empty 2) Move data onto it 3) Wipe out the original NTFS drive 4) Create 1.5 TB sparse files (5 of them) on the old NTFS drive 5) Create raidz2 on the 1.5 TB files (mount as loopback if necessary) Note: I realize this defeats the benefits of the raidz, the drive dies and I lose everything on it. 6) Copy data from the 1 TB ZFS volume to the psuedo/fake raidz array (I'd set up an rsync or something) This way I still have -some- redundancy should 1 of the 2 drives fail. As I get new drives, I'll replace the loopback device with the physical device. This way I'll slowly gain the redundancy I desire (raidz2), while still being redundant while the amount of data I have is low. Any thoughts on this? I don't see why it shouldn't work, but I've only been tinkering with ZFS for 2 days now and this is all unexplored territory. P-Chan -- This message posted from opensolaris.org _______________________________________________ zfs-discuss mailing list zfs-discuss@opensolaris.org http://mail.opensolaris.org/mailman/listinfo/zfs-discuss
