All,
I was wondering why "zfs destroy -r" is so excruciatingly slow compared to
parallel destroys.
On my x4500, for example, after having created 1000 filesystems named
pool/blub2/0000
[...]
pool/blub2/0999
and keeping them empty, a subsequent destroy with
# time zfs destroy -r pool-0/blub2
yields
real 5m17.657s
user 0m0.184s
sys 0m1.831s
while a little handy-work with
# time for i in `zfs list | awk '/blub2\\// {print $1}'` ;\
do ( zfs destroy $i & ) ; done
yields
real 0m8.191s
user 0m6.037s
sys 0m16.096s
An 38.8 time improvement (at the cost of some extra CPU load)
Why is there so much overhead in the sequential case? Or have I oversimplified
the issues at hand with this simple test?
Joep
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