That is 1.30 angstroms. Thanks again.

Keith L. Constantine, Ph. D.

Sr. Research Investigator II
Mechanistic Biochemistry
Bristol Myers Squibb Research and Development
P.O. Box 4000
Princeton, NJ 08543-4000
Tel: (609)-252-6926
Fax: (609)-252-6012
e-mail: keith.constant...@bms.com


>-----Original Message-----
>From: Constantine, Keith
>Sent: Monday, October 21, 2013 8:36 AM
>To: 'Charles Schwieters'
>Cc: xplor-...@nmr.cit.nih.gov; Mueller, Luciano; Metzler, William
>Subject: RE: changing van der Waals radius without modifying an atom
>type
>
>
>Hi Charles,
>
>
>Thanks!
>
>I'm using a somewhat older force field (see below. The Lennard-Jones
>potential is implemented differently. For example S (radius = 1.05
>angstroms) sigma is 3.7458 in this setup. After double checking the
>formula given (sigma*2^(-5/6))I believe is wrong - it should include
>division by 2 . So for S I get 3.7458(0.561)/2 = 1.05 angstroms.
>
>I pretty sure the sigma I should use is 4.635 to approximate r = 1.20
>angstroms.
>
>
>    Keith
>
>! the non-bonded parameters are approximately the same as
>! DISMAN's large radii for repel=0.9, and as DISMAN's small
>! radii for repel=0.75. (ECEPP2)
>! the epsilon values are generally not used (and should not be)
>! with this force field
>! the radius is sigma*2^(-5/6)
>!
>!                   eps     sigma       eps(1:4) sigma(1:4)  repel:  1.0
>0.9     0.8     0.75
>!
>radii
> nonbonded  C       0.0903   3.3409      0.0903   3.3409   !
>1.875   1.688   1.5     1.406
> NONBonded  C6R     0.05000   3.6349   0.10000   3.1360    ! added
>02/19/10 kc from quanta params
> NONBonded  CA      0.120    3.3409      0.120    3.3409
> NONBonded  CB      0.145    3.3409      0.145    3.3409
> NONBonded  CC      0.145    3.3409      0.145    3.3409
> NONBonded  CN      0.145    3.3409      0.145    3.3409
> NONBonded  CP      0.1450   3.3409      0.1450   3.3409
> NONBonded  CR      0.1200   3.3409      0.1200   3.3409
> nonbonded  CT      0.0903   3.3409      0.0903   3.3409
> NONBonded  CV      0.1200   3.3409      0.1200   3.3409
> NONBonded  CW      0.1200   3.3409      0.1200   3.3409
> NONBonded  CX      0.1450   3.3409      0.1450   3.3409
> nonbonded  H       0.0498   2.2272      0.0498   2.2272   !
>1.250   1.125   1.0     0.9375
> nonbonded  HRNE    0.0498   2.2272      0.0498   2.2272   !
>1.250   1.125   1.0     0.9375
> nonbonded  HA      0.0045   2.2272      0.0045   2.2272
> nonbonded  HC      0.0498   2.2272      0.0498   2.2272
> nonbonded  N       0.1592   3.0068      0.1592   3.0068   !
>1.688   1.519   1.350   1.266
> NONBonded  NA      0.1592   3.0068      0.1592   3.0068
> NONBonded  NB      0.1592   3.0068      0.1592   3.0068
> nonbonded  NC2     0.1592   3.0068      0.1592   3.0068
> nonbonded  NH1     0.1592   3.0068      0.1592   3.0068
> nonbonded  NH2     0.1592   3.0068      0.1592   3.0068
> nonbonded  NH3     0.1592   3.0068      0.1592   3.0068
> nonbonded  O       0.2342   2.7755      0.2342   2.7755   !
>1.558   1.402   1.246   1.168
> nonbonded  OC      1.0244   2.7755      1.0244   2.7755
> nonbonded  OH      0.2342   2.7755      0.2342   2.7755
> nonbonded  S       0.0239   3.7458      0.0239   3.7458   !
>2.102   1.892   1.682   1.577
>
>Keith L. Constantine, Ph. D.
>
>Sr. Research Investigator II
>Mechanistic Biochemistry
>Bristol Myers Squibb Research and Development
>P.O. Box 4000
>Princeton, NJ 08543-4000
>Tel: (609)-252-6926
>Fax: (609)-252-6012
>e-mail: keith.constant...@bms.com
>
>>-----Original Message-----
>>From: Charles Schwieters [mailto:char...@schwieters.org]
>>Sent: Friday, October 18, 2013 2:04 PM
>>To: Constantine, Keith
>>Cc: Charles Schwieters; xplor-...@nmr.cit.nih.gov; Mueller, Luciano;
>>Metzler, William
>>Subject: Re: changing van der Waals radius without modifying an atom
>>type
>>
>>
>>Hi Keith--
>>
>>> I used:
>>>
>>> parameter
>>>   nonbond (resid X and name HN) 0.0498 4.0000   0.0498 4.000
>>> end
>>>
>>> If I am correct, setting sigma to 4.000 should correspond to a
>>> radius of ~1.30 angstroms, which is close enough for this
>>> application.
>>>
>>
>>
>>Rvdw = sigma 2^(1/6) / 2
>>
>>so, to get a radius of 1.3 angstrom, use sigma=2.316 angstrom.
>>
>>best regards--
>>Charles

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