On 7/22/23 3:47 PM, Michael K wrote:
To answer Grant's question. Yes, I had added the X ports but I've now turned
off the firewall just to be sure.
ACK
I generally don't like disabling the firewall. -- I'm currently
tilting at RPC for NFS to get it to work through a firewall.
But sometimes disabling the firewall, or better pin-holing the pair of
communicating systems, is the better part of valor or at least sanity
preserving during troubleshooting.
Here is the wireshark conversation.
Thank you.
I'm not knowledgeable enough to recognize the issue..
I don't remember the last time I looked at X11 traffic with a sniffer.
So, I could be completely off my rocker with my analysis (below).
N.B. I've tried to tweak the white space so that columns line up in a
way that I think is slightly better.
1 0.000000000 192.168.1.16 192.168.1.1 TCP 60 6915 → 6001
[SYN] Seq=0 Win=0 Len=0 MSS=1416
2 0.000165997 192.168.1.1 192.168.1.16 TCP 58 6001 → 6915
[SYN, ACK] Seq=0 Ack=1 Win=64240 Len=0 MSS=1460
3 0.005196101 192.168.1.16 192.168.1.1 TCP 60 6915 → 6001
[ACK] Seq=1 Ack=1 Win=1416 Len=0
This looks like a standard TCP 3-way handshake to me.
4 0.008854195 192.168.1.16 192.168.1.1 X11 66
Initial connection request
This looks like a message from the sniffer saying that X11 protocol is
starting.
5 0.008914324 192.168.1.1 192.168.1.16 TCP 54 6001 → 6915
[ACK] Seq=1 Ack=13 Win=64228 Len=0
6 0.009029932 192.168.1.1 192.168.1.16 TCP 62 6001 → 6915
[PSH, ACK] Seq=1 Ack=13 Win=64228 Len=8 [TCP segment of a reassembled PDU]
I assume that's X11 application protocol traffic.
Maybe turning up verbosity would show more details. Though I don't know
that such is warranted. (See comments below the packet capture.)
7 0.009086172 192.168.1.1 192.168.1.16 X11 110
Initial connection reply
8 0.009149782 192.168.1.1 192.168.1.16 TCP 54 6001 → 6915
[FIN, ACK] Seq=65 Ack=13 Win=64228 Len=0
9 0.017057921 192.168.1.16 192.168.1.1 TCP 60
[TCP ZeroWindow] 6915 → 6001 [ACK] Seq=13 Ack=66 Win=0 Len=0
10 0.019632130 192.168.1.16 192.168.1.1 TCP 60
[TCP ZeroWindow] 6915 → 6001 [ACK] Seq=13 Ack=66 Win=0 Len=0
11 0.023341315 192.168.1.16 192.168.1.1 TCP 60
[TCP ZeroWindow] 6915 → 6001 [ACK] Seq=13 Ack=66 Win=0 Len=0
I assume that's X11 application protocol traffic.
12 0.083569102 192.168.1.16 192.168.1.1 TCP 60 6915 → 6001
[FIN, PSH, ACK] Seq=13 Ack=66 Win=0 Len=0
13 0.083647415 192.168.1.1 192.168.1.16 TCP 54 6001 → 6915
[ACK] Seq=66 Ack=14 Win=64228 Len=0
This looks like the start, but incomplete capture, of a normal TCP 4-way
connection terminating. ...16 tells ...1 that it wants to terminate the
TCP connection via the FIN flag. ...1 replies acknowledging ...16's FIN.
Also, yes the X display is 1 on this server.
This packet capture makes it obvious to me that the X11 client
(application) is successfully initiating a TCP connection and talking
the X11 protocol to the X11 (display) server. This means that:
1) The firewall is not interfering.
2) X11 display :1 is the proper display.
3) There do not appear to be any network / IP / TCP issues with the
communication.
4) This seems to be an X11 protocol level problem.
5) This seems to NOT be a networking problem.
Turning up the verbosity on the capture /may/ provide more details. Or
seeing if the network sniffer has the ability to produce more details
about the actual X11 protocol. Wireshark / Tshark can be extremely
impressive.
I think I would be inclined to make sure that I had the *X11* /console/
showing to see if any errors shed some light on things.
I'd also look to see if any additional logging could be enabled for the
X11 (display) server and / or X11 client (application) to see if it's
possible to get either of them to provide any additional diagnostic data.
Aside: It's my understanding that there are a couple of common TCP
connection termination methods:
1) Each end sends it's own FIN and receives an ACK from the other end.
L ---FIN------> R
L <------ACK--- R
L <--FIN------- R
L -------ACK--> R
2) One end sends it's FIN to the other end, the other end ACKs the
first's FIN /and/ sends it's own FIN at the same time, and then the
first end ACKs the second end's FIN.
L ---FIN------> R
L <--FIN,ACK--- R
L -------ACK--> R
Grant. . . .