I have a laptop that I usually connect to an external monitor. I use
Ubuntu 16.04 and Gnome 3.18.5. When I do connect to the external
monitor, I like to turn the laptop screen off. I can do that by going to
System Settings, Screen Display, selecting the built-in display and then
clicking "off". I'd like to automate the process. I found a script that
claimed to do that at startup. It's as follows:
#!/bin/bash
sleep 15
EXTERNAL_OUTPUT="DP1"
INTERNAL_OUTPUT="eDP1"
xrandr |grep $EXTERNAL_OUTPUT | grep " connected "
if [ $? -eq 0 ]; then
xrandr --output $INTERNAL_OUTPUT --off --output $EXTERNAL_OUTPUT
--auto
else
xrandr --output $INTERNAL_OUTPUT --auto --output $EXTERNAL_OUTPUT --off
fi
I made the script a startup application.
It works as advertised when the external monitor is connected. However,
when the external monitor is not connected, I first see my desktop on
the laptop screen as I would like it. Then, when the script wakes up and
runs, the bottom panel on my desktop suddenly jumps to the top of the
screen and comes to rest immediately below the top panel. I can't find
any reports of this happening to anyone else.
If anyone could explain to me why the script is causing this behavior
and tell me how to correct it, I'd be very grateful.
Thanks,
Leslie
--
Leslie Katz
email: lesliek [at] mymts [dot] net
Please visit http://ssrn.com/author=1164057 to find hyperlinks
to papers that I’ve written on literary and legal topics
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