So is the hash table cleared automagically or does the user need to do it?
It would seem one might want to clear it during "system" startup perhaps?
Mike W9MDB
On Saturday, August 14, 2021, 08:05:30 AM CDT, Bill Somerville via
wsjt-devel <[email protected]> wrote:
Mike,
there is no CRC in the WSPR protocol, details are here:
https://www.physics.princeton.edu/pulsar/K1JT/WSPR_2.0_User.pdf
Hash codes are using in WSPR Type 2 and Type 3 messages where the call or
locator specified to send does not fit into the 28-bit or 15-bit respective
source encodings. Hash codes are needed to carry call information between a
pair of transmissions allowing the second to be decoded using a hash code
lookup.
Hash values would be useless if they were not saved, the lookup relies on the
relatively low probability of a hash collision if the hash table is maintained
in a MRU (most recently used) ordering. Also wsprd is used stand-alone by
several systems to decode each received period, without a file of hash codes it
could never do a successful hash lookup!
Hash collision likelihood increases if the hash table is allowed to get too
big, this is because a message with the hash code may be received having never
received the first message with the matching call. It makes sense to clear the
hash table file occasionally to avoid this happening too often.
73
Bill
G4WJS.
On 14/08/2021 13:40, Black Michael via wsjt-devel wrote:
Doesn't WSPR also use the CRC in messages? So it would be a combination of
collision + valid CRC. The 50/50 point for 32768 values is 214. Why does WSPR
remember the hash value?
We do see bogus matches in FT8 modes and such -- not real often but every
once in while a callsign hash will match a random decode....same 15 bit hash
being used for that too.
Given the much lower WSPR counts I would expect "valid" collisions to be
pretty rare.
Mike W9MDB
On Friday, August 13, 2021, 05:41:12 PM CDT, Phil Karn via wsjt-devel
<[email protected]> wrote:
The hash function used in wspr is 15 bits wide, i.e., there can be
32,768 values. This may seem like a lot, but the "birthday paradox" says
that the probability of a collision grows faster than you might expect
as the set size grows. It comes from the fact that you only need ~23
people to have a 50% probability that two of them have the same birthday.
A very rough approximation is that the probability of a collision is 1/2
when the set size is equal to the square root of the hash size. For 15
bits, that's about 180. My hashtable.txt for 40m currently has 353 entries.
Has anyone seen a collision in practice? If one occurs, the most recent
duplicate entry is most likely the correct one. Requiring a match in the
first 4 characters of the grid square would also seem to greatly reduce
the problem.
Phil
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